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3 Dfrac 1 2 Times 3 Dfrac 1 2

Hypotenuse therefore If \\[\\dfrac{{(\\cos {\\text{ a)}}}}{3} = \\dfrac{{(\\cos {\\text{ b

If \\[\\dfrac{{(\\cos {\\text{ A)}}}}{3} = \\dfrac{{(\\cos {\\text{ B

If \\[\\dfrac{{(\\cos {\\text{ A)}}}}{3} = \\dfrac{{(\\cos {\\text{ B

If \\[\\dfrac{{(\\cos {\\text{ A)}}}}{3} = \\dfrac{{(\\cos {\\text{ B

If \\[\\dfrac{{(\\cos {\\text{ A)}}}}{3} = \\dfrac{{(\\cos {\\text{ B

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